(2x+3)(x+4)=2x^2+11x+12

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Solution for (2x+3)(x+4)=2x^2+11x+12 equation: 



(2x+3)(x+4)=2x^2+11x+12

We move all terms to the left:

(2x+3)(x+4)-(2x^2+11x+12)=0

We get rid of parentheses

-2x^2+(2x+3)(x+4)-11x-12=0

We multiply parentheses ..

-2x^2+(+2x^2+8x+3x+12)-11x-12=0

We get rid of parentheses

-2x^2+2x^2+8x+3x-11x+12-12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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